SetSoundPitch

I am trying to convert one note into a range of notes and I think I can do it using that function. However starting with middle C (or any other note for that matter) I don't know what values to input to get the different notes...

If anyone could help at all it would be much appreciated ^.^

In the modern tuning, there are 12 notes from C to C up an octave. They are evenly spaced in the logarithmic frequency domain. So, to go up n half steps, you compute (2.^(1./12.))^n

My guess would be that, if SetSoundPitch, this is the right domain for it.

um could you give me an example please I don't quite get how it works

SetSoundPitch(snd,Pow(2.,4./12.)) should increase the pitch of snd four half steps or a major third.

So it would go from C to C#, Db, D, D#?

And one more thing I cant find what notes have #'s and b's because I don't think all of them do...

EDIT: I found a note list and I believe that the 4th half-step would actually be C, C#, D, D#, E with E being the note. Is that correct?

EDIT also according to this formula "(2.^(1./12.))^n" wouldn't the formula actually convert to "SetSoundPitch(snd,Pow(n, Pow(2,1/12))" and as such 4 half steps be SetSoundPitch(snd,Pow(4, Pow(2,1/12))

4 half-steps up from "C" is "E"; the 4th tone is "D#"/"Eb".

Ok I get that now tks for the list it helps :)

as for the formula one or the other was wrong is it correct as "SetSoundPitch(snd,Pow(n, Pow(2,1/12))" or "SetSoundPitch(snd,Pow(2.,n./12.))"

PS: @pyro "The Spell Request Thread — Currently Open" closed the thread?

(a^n)^m = exp(log((a^n)^m)) = exp(m log(a^n)) = exp(m n log(a)) = exp(log(a^(m n))) = a^(m n)

and again im confused :/ what is the value of a, m, and n

Or where you just saying that both formulas are the same?